(1/4)x^2-8x+64=0

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Solution for (1/4)x^2-8x+64=0 equation: 



(1/4)x^2-8x+64=0



Domain of the equation: 4)x^2!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

(+1/4)x^2-8x+64=0

We add all the numbers together, and all the variables

-8x+(+1/4)x^2+64=0

We multiply all the terms by the denominator


-8x*4)x^2+(+64*4)x^2+1=0

We add all the numbers together, and all the variables

-8x*4)x^2+256x^2+1=0

Wy multiply elements

-32x^2=0

a = -32; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-32)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{-64}=0$

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